Some basic definition questions of set theory

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SUMMARY

The theorem states that if f: A -> B is a surjection and g: B -> C is also a surjection, then the composition g ∘ f: A -> C is a surjection. The proof involves demonstrating that for every element c in C, there exists an element a in A such that g(f(a)) = c. The discussion confirms that the logical structure of the proof is correct, emphasizing the necessity to show the existence of a corresponding a for each c.

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Ed Quanta
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I have to prove the following theorem,

1) If f:A->B is a surjection, and g:B->C is a surjection then g dot f:a->C is a surjection

Well this makes sense and I am not sure how to PROVE it

Is it sufficient to say the following

if for every element b of B, there exists a element a of A such that f(a)=b and same for B->C for g(b)=c is true, Then

for every element of c in C, there must exist an a of A such that g(f(a))=c since for every b in B there exists f(a)=b, and we know g(b)= c is true for every element of c,
 
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Yes that's the right idea though the phrase 'we know g(b)=c is true for every..' is, erm, not what you want to write, but I think that is just the sentence structure nothing more.

You must show that for all c in C, there is an a in A such that gf(a)=c, which is what you've done.
 

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