|Feb23-08, 07:59 PM||#1|
Inverse Trig Integral
I don't if its because I'm tired or what but I can't seem to integral the follow
[tex]\int (-x+1)/(x^2+1)[/tex] I tried substitution, u=x^2+1 du=2x, doesn't appear to be anything there, u=-x+1, du=1, again doesn't appear to be anything there. The book shows it simply as tan^-1 (x), don't think its a partial fraction. Any ideas?
|Feb23-08, 08:02 PM||#2|
How about now?
|Feb23-08, 08:08 PM||#3|
blah, I should of seen that, thanks. :)
|Similar Threads for: Inverse Trig Integral|
|Inverse Trig Derivatives||Calculus & Beyond Homework||7|
|Inverse trig derivative||Calculus & Beyond Homework||1|
|d/dx of Inverse trig||Calculus & Beyond Homework||8|
|Inverse Trig Derivatives||Introductory Physics Homework||4|
|Help on inverse trig differentiation||Introductory Physics Homework||3|