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De Morgan duality 
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#1
Feb2608, 12:43 PM

P: 62

I had many unsuccessful attempt to prove De Morgan duality law, for the application in electrical enginnering. Is there anyone who can help me about this?



#2
Feb2608, 01:29 PM

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If you are talking about this statement, isn't it enough to just prove
 not (P and Q) <=> (not P) or (not Q)  not (P or Q) <=> (not P) and (not Q) and if not, what exactly do you call the "de Morgan duality law"? 


#3
Feb2608, 01:43 PM

P: 62

I tried to ask the application in digital circuit design. For example, F = A + B and F^D = A.B
Isn't it duality law? 


#4
Feb2608, 02:39 PM

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P: 4,300

De Morgan duality
I don't know, I'm not into digital circuit design.
But what exactly do you want to prove? That if F is a proposition, so is F^D? (That's what I make out of this reference) 


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