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Arrhenius equation |
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| Mar2-08, 11:14 AM | #1 |
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Arrhenius equation
1. The problem statement, all variables and given/known data
A common rule of thumb is that temperature 10 degrees C for many reactions will double the reaction rate. Derive under what conditions this is true. 2. Relevant equations ln(k) - ln(2k) = (-Ea/R) [(1/T1)-(1/T2)] 3. The attempt at a solution I know I have to start off by plugging in values for T1 and T2, but what exactly am I trying to solve for? My teacher said to solve for Ea, but that is the measure of kinetic energy needed for reaction....what do I solve for when looking for reaction rate? Also, can I leave the rate constants in or should I plug in actual values for those as well? |
| Mar2-08, 02:49 PM | #2 |
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I had the exact same question on a quiz, but instead we were given the room temperature. Indeed you do want to solve for Ea. You'll want to plug in values for ln k & temp. Think arbitrary values for what you want to plug in for the numbers, as long as they all relate to each other.
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| Mar2-08, 03:04 PM | #3 |
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But what value of Ea am I looking for? If I'm plugging in all my values into that equation that I typed up there, of course I'll just get a value for Ea.
And why am I solving for Ea anyway? How will I know what the reaction rate is if I know Ea? |
| Mar2-08, 05:04 PM | #4 |
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Arrhenius equation
The equation you are using is incorrect.
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| Mar2-08, 06:38 PM | #5 |
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I'm using the same equation as that....I'm just changing the locations of the corresponding k1/T1 and k2/T2 values.
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| Mar3-08, 04:22 PM | #6 |
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Nice derivation, Roco. Rewrite the expression and solve for Ea. Use "T1+10" in place of "T2".
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