|Mar14-08, 07:23 AM||#1|
light wavelengths of 520nm and 630nm passes through a diffraction grating that contains 6000lines/cm. a) sketch a diagram of the image produced from m=0 to m=2. label the order of each fringe.b) calculate the angles for the first and second-order maxima that would appear on the screen. c) What is the lowest value of m for which the 520-nm line no longer exists?
For part b....what wavlength do i use to find the angles for the first and second oreder maxima???....:S
|Mar14-08, 10:18 AM||#2|
can anyone help me ...please..
|Mar14-08, 01:24 PM||#3|
They have different angles in both the first and second maxima.
sintheta cannot exceed one
so calculate the n your own
you should calculate and do homework yourself.
I am to guide you, not to help u finish your homework
|Mar14-08, 01:30 PM||#4|
this is not my homework..It was my homework...but i got it wrong, unfortunately my teacher did not write the correct answer....as my exam is approching...i am preparing for it. I am doing this course through ilc, ilc tutors are not available right now because of the break, thats why i wanted to know the answer to this question.
So for part b) i am supposed to find the first and sec order maxima for both wavelengths?......i see now that's why i got it wrong in first place.
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