## Diffraction Grating

light wavelengths of 520nm and 630nm passes through a diffraction grating that contains 6000lines/cm. a) sketch a diagram of the image produced from m=0 to m=2. label the order of each fringe.b) calculate the angles for the first and second-order maxima that would appear on the screen. c) What is the lowest value of m for which the 520-nm line no longer exists?

For part b....what wavlength do i use to find the angles for the first and second oreder maxima???....:S

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 Both. They have different angles in both the first and second maxima. c) (10^-2/6000)sintheta =n(520*10^-9) sintheta cannot exceed one so calculate the n your own you should calculate and do homework yourself. I am to guide you, not to help u finish your homework

## Diffraction Grating

this is not my homework..It was my homework...but i got it wrong, unfortunately my teacher did not write the correct answer....as my exam is approching...i am preparing for it. I am doing this course through ilc, ilc tutors are not available right now because of the break, thats why i wanted to know the answer to this question.
So for part b) i am supposed to find the first and sec order maxima for both wavelengths?......i see now that's why i got it wrong in first place.