What is the energy released during alpha particle emission in Am-241 decay?

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SUMMARY

The energy released during alpha particle emission in Americium-241 (Am-241) decay is 5.486 MeV, calculated using the mass-energy equivalence equation E=mc². This decay reaction produces Helium-4 (He-4) and Neptunium-237 (Np-237). The mass difference between Am-241 and the products is 4.0081 amu, which directly influences the energy released. It is important to note that the energy released varies across different decay reactions due to differences in mass defects.

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Whats the energy released when an alpha particle is emitted, say for example, from Am-241 -> He-4 + Np-237 ?

Is it the same for all decay reactions?
 
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No, the same amount of energy is not released for all alpha decays or all decays for that matter. Have you heard of binding energy or mass defect? Look at the mass of http://www2.bnl.gov/CoN/nuc/A/Am241.shtml

Its been a couple of years since I last made big atoms into small atoms with a few neutrons to boot, but the above should still hold true.
 
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The energy released when an alpha particle is emitted can be calculated using the mass-energy equivalence equation, E=mc^2, where E is the energy released, m is the mass difference between the parent and daughter nuclei, and c is the speed of light. In the case of Am-241 decay to He-4 and Np-237, the energy released would be 5.486 MeV (mega electron volts). This is because the mass of Am-241 is 241.05682 amu (atomic mass units) and the combined mass of He-4 and Np-237 is 237.04872 amu, resulting in a mass difference of 4.0081 amu.

The energy released in alpha decay can vary depending on the specific decay reaction, as it is determined by the mass difference between the parent and daughter nuclei. Therefore, the energy released may be different for different decay reactions. However, in general, the energy released in alpha decay is typically in the range of a few MeV.
 

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