Determine the time rate at which heat is supplied to the engine

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Homework Help Overview

The problem involves a heat engine, specifically an oil-fired steam turbine driving an electric power generator with a specified power output and efficiency. The original poster seeks to determine the time rate at which heat is supplied to the engine.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of efficiency for a heat engine and its relation to energy input and output. There are questions about how to apply the efficiency formula and whether the power output needs to be converted.

Discussion Status

Some participants have provided guidance on the efficiency equation and its components, while others express confusion about the application of the formula. Multiple interpretations of the problem setup are being explored, but no consensus has been reached.

Contextual Notes

One participant notes a lack of instruction on the topic from their teacher, which may affect their understanding of the problem. There is also mention of the need to consider units and the representation of efficiency in calculations.

bigmikey800
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Homework Statement


a heat engine consists of an oil fired steam turbine driving an electric power generator with a power output of 120 megawatts. the efficiency of the heat engine is 40 percent. How do determine the time rate at which heat is supplied to the engine?


Homework Equations





The Attempt at a Solution


 
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To get help at the Homework Forum, you have to show your attempt to solve the problem first. So the first thing to start with would be:

We know the efficiency of the engine is 40% = 0.4. What is the definition of efficiency for a heat engine?
 
my teacher didnt teach us how to do this so I am completely lost
 
Have you been shown yet the equation

efficiency = (net work or energy output) / ( heat or energy input) ?

What would be the input and the output in your problem statement?
 
The efficiency is 40%, the output is 120 megawatts. Therefore, to fine the (heat or energy input) i can just divide (Efficiency)/(network or energy output) to find the anwswer? Also, do i have to change 120 megawatts or can i just leave it?
 
bigmikey800 said:
The efficiency is 40%, the output is 120 megawatts. Therefore, to fine the (heat or energy input) i can just divide (Efficiency)/(network or energy output) to find the anwswer?

Check your algebra: if you're solving for the input (heat supply to the engine), what should your quotient be?

Also, do i have to change 120 megawatts or can i just leave it?

You can just leave it. The same formula also work for power, since it is the rate at which work or energy is transferred:

efficiency = (net power output) / (power input)

Don't forget that, while efficiency is often expressed as a percentage, it must be used in the equations as a fraction. So the efficiency here is 0.4 .
 

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