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limits..proving they exist??? |
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| Apr25-04, 04:56 AM | #1 |
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limits..proving they exist???
Wot do u have to do to prove that an intergral exists.?? I know how to do it if the integrals bounds are given ( example, [a,b]) but wot if the integral is from x till infinity??
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| Apr25-04, 05:46 AM | #2 |
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Recognitions:
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In the same wasy as infinite sums, work out the integral from a to b and then let b tend to infinity. Eg
integral of 1/x from a to b is log(b) - log(a), which tends to infinity as b tends to infinity so the integral doesn't exist. integral of 1/x^2 from a to be is 1/a^2-1/b^2, which tends to 1/a^2 as b tends to infinity so the infinite integral exists. If you wish to integrate from minus infinity to infinity, you must do the integral from a to b and let a and b tend to infinity independently. Thus the improper integral of sin(x) over the real line does not exist even though you can choose the interval to be [-a,a] and get an answer of zero (other choices will give different answers hence the integral does not exist) |
| Apr25-04, 06:01 AM | #3 |
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How will you do
[tex]\int\frac{sinx}{x}dx[/tex] from zero to infinity. Which can be written as a alternating series T subscript n =[tex]\mid\int\frac{sinx}{x}dx\mid[/tex] over intervals ([tex](n-1)\pi,n\pi[/tex]) but how do show as n tends to infinity that T(n) tends to 0??? cos i cant integrate it |
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