|Apr3-08, 11:37 PM||#1|
Limit Comparison Test for series
I have been given the series
sum 1/sqrt(3n-2) from n=1 to infinity
I am supposed to use the limit comparison test, and the comparison series my book suggests is sum 1/sqrt n from n=1 to infinity, which I know is a divergent p series
However, when I take the limit of one divided by the other I come up with 0.
lim n -> infinity for (sqrt n)/(sqrt 3n-2) = 0
What am I doing wrong?
|Apr4-08, 12:12 AM||#2|
Nevermind, I figured it out.
This Limit Comparison test shows that the series diverges because the limit is 1/sqrt3.
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