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2nd fundamental theorem of calculus 
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#1
Apr2604, 03:40 PM

P: 2

Can some on pleases explain this too me. I have an AP book, and i am to do a few problems out of it for class, and but cant find it in there ANY WHERE. Any help would be superb!
Jacob 


#2
Apr2604, 04:07 PM

P: 87

Mathworld says:
http://mathworld.wolfram.com/SecondF...fCalculus.html In my book, this is simply called "the fundamental theorem of calculus", and mathworld's first t. of c. is mentioned later than this, so I can understand your confusion. 


#3
Apr2604, 04:32 PM

P: 204

Finney's book has this backwards... The second F of C is the Integral Evaluation Theorem... Which is the mathworld's 1st...
Its hand stuff! 


#4
Apr2604, 04:55 PM

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PF Gold
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2nd fundamental theorem of calculus
I've seen it both ways in several books. Luckily, no teacher has ever asked me to state FTC #1 or state FTC #2, they've only asked me to be able to use them.
Did you try any of the problems yet? 


#5
Apr2604, 05:29 PM

P: 617

Do you need to understand the proofs? Or just understand the idea?
FTC#2 says [itex] \int^b_a f(x)dx = F(b)  F(a) [/itex] where the antiderivative of f(x) is F(x) So what you are probably using this Thrm for is evaluating definite integrals (ones with A and B stated). So what you do is find the antiderivative of f(x) i.e. F(x), and then evaluate that antiderivative at a and b, then take the absolute value of their difference. For example if we wanted to evaluate: [itex] \int^5_1 3x^2dx [/itex] we would first find the anti derivative of 3x^2. Which is x^3. Then we would evaluate x^3 at 1 and 5 which gives us, 1 and 125. We subtract 1 from 125 and get 124, hence: [itex] \int^5_1 3x^2dx = 124[/itex] 


#6
Apr2604, 06:15 PM

P: 2

thanx you guys. I know how to do those with my eyes closed, its just that my AP book has a real habit of doing things w/o thouroughly explaining them. thanx again ill tell my friends about this site!
Jacob 


#7
Sep2104, 09:07 PM

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2nd FTC: If f is any riemann integrable function on the closed bounded interval [a,b], and G is a Lipschitz  continuous function such that for every point x where f is continuous, G is diiferentiable at x with G'(x) = f(x), then the integral of f from a to b, equals G(b)G(a).
Recall that G is lipschitz continuous on [a,b] if there exists a constant K such that for all points u,v in [a,b] we have G(v)  G(u) <= Kvu. 


#8
Sep2204, 09:21 PM

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PF Gold
P: 2,327

Is the first theorem just:
y=x^n dy/dx=nx^n1 Is that it? I wrote general proof for the derivative of a function x^n. Using limits of course, and I ended with nx^n1, which is what you are suppose to get. I never seen the proof yet, and it would be great to do it independently. So, what is the 1st Fundamental Theorem(in most books)? 


#9
Sep2204, 09:27 PM

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in most books it says that if f is continuous on [a,b] and G(x) is the integral of f from a to x, then G is differentiable on [a,b] and G'(x) = f(x) for every x in [a,b].
The more general statement is that if f is a Riemann integrable function on [a,b] and G(x) again is the injtegral of f from a to x, then G is Lipschitz continuous, and G is differentiable with G'(x) = f(x) at those points where f is continuous. Then to derive the 2nd thm from the first you need the generalized mean value theorem, that a function G which is lipschitz continuous and has derivative equal to zero almost everywhere (i.e. except on a set of measure zero) is constant. in most books the 2nd thm just says that if f is continuous on [a,b] and G is continuous on [a,b] with G'(x) = f(x) for all x in (a,b), then the integral of f from a to b, equals G(b)G(a). 


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