What is the change in KE of the proton?

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Homework Help Overview

The discussion revolves around calculating the change in kinetic energy (KE) of a proton moving in an electric field. The problem involves understanding the relationship between electric fields, potential difference, and kinetic energy in the context of charged particles.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the formula for kinetic energy related to electric fields and question the definitions of terms used in the context. There is an attempt to clarify the correct relationships and formulas applicable to the situation.

Discussion Status

Some participants are providing clarifications on the terms and concepts involved, while others are questioning the accuracy of the initial formula presented. There is an ongoing exploration of the correct approach to calculate the change in kinetic energy.

Contextual Notes

Participants are discussing potential misunderstandings regarding the definitions of terms such as "charge of potential" and "velocity of acceleration." The problem also includes specific values for the proton's mass and charge, as well as the distance moved in the electric field.

Dx
A proton moves .1 m along the direction of an electric field of magnitude 3 V/m. What is the change in KE of the proton?

Is this the corrrect formula? KE = Q_pV_accel

Through substition i came up with an swer of 3.2x10^-20J but i don't think its correct?
Can you help me solve for this please?

Thanks!

Dx :wink:
 
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Originally posted by Dx
Is this the corrrect formula? KE = Q_pV_accel

Can you explain what those terms mean?
 


Originally posted by Tom
Can you explain what those terms mean?

Sure Tom,

KE=Kinetic Energy
Q_p=Charge of potential
V_accel=velocity of acceleration

Its not the correct formula huh?
 
Dx,

There is no such thing as a "charge of potential" or "velocity of acceleration". I think you have those concepts muddled up. The kinetic energy K that a charge q acquires while being accelerated through an potential difference* V=Ed is:

K=qV=qE/d

*I can use V=Ed because that is valid for parallel plate capacitors.
 
A proton moves .1 m along the direction of an electric field of magnitude 3 V/m. What is the change in KE of the proton?
proton mass = 1.6e-27 kg
proton charge = 1.6e-19 C
distance = 0.1m
E = 3 V/m
mv2/2 = energy (non-relativistic)
KE=qE/d...
just pick up the calculator.
 

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