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Determining the Index of Refraction 
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#1
Apr908, 04:35 PM

P: 452

1. The problem statement, all variables and given/known data
PART A) What is the frequency of blue light that has a wavelength of 450 nm? PART B) What is the frequency of red light that has a wavelength of 650 nm? PART C) What is the index of refraction of a material in which the redlight wavelength is 450 nm? 2. Relevant equations [tex]v = f \lambda[/tex] 3. The attempt at a solution PART A [tex]f = \frac{v}{\lambda} = \frac{3*10^8}{450*10^{9}} = 4.62*10^{14} Hz[/tex] *CORRECT* PART B [tex]f = \frac{v}{\lambda} = \frac{3*10^8}{650*10^{9}} = 6.67*10^{14} Hz[/tex] *CORRECT* PART C Not sure. Can someone point me in the right direction? 


#2
Apr908, 04:44 PM

P: 66

I wanna help but I'm not sure if this is right. The index if refraction is c/v. Maybe you need to use the frequency you got from part b and determine the new velocity of the red light with the new wavelength? Then divide c by this to get the refraction index?



#3
Apr908, 05:45 PM

P: 452




#4
Apr908, 05:49 PM

P: 66

Determining the Index of Refraction



#5
Apr908, 06:03 PM

Sci Advisor
HW Helper
Thanks
P: 25,228

negatifzeo is correct. The frequency of the light doesn't change. Only the velocity and hence the wavelength.



#6
Apr908, 06:04 PM

P: 452

Yep, you were correct. I multiplyed the frequncy I got from Part B by the 450 nm to get v, then I just divided it c by it to get the index of redraction.
Thank you. 


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