|Apr13-08, 07:39 PM||#1|
Equation of a line/plane
1. The problem statement, all variables and given/known data
Where does the line through A(1,0,1) and B(4,-2,2) intersect the plane x+y+z=6?
2. Relevant equations
r= r_0 + tv
3. The attempt at a solution
The line through A and B is the vector AB and can be found by subtracting the A components from the B components. So B-A= <3,-2,1>.
They give x+y+z=6 so the components of that vector is <1,1,1>.
Not sure where to go from here....
|Apr13-08, 07:43 PM||#2|
Put the components of your parametric equation for the line, e.g x=1+3t into the equation for the plane and solve for t, please? The normal vector to the plane doesn't have much to do with it.
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