How to Find the Ratio in a Geometric Progression with Non-Consecutive Terms

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Discussion Overview

The discussion revolves around finding the common ratio in a geometric progression (GP) when given non-consecutive terms, specifically the 7th and 26th terms. Participants explore the challenges of determining the ratio without knowledge of the first term and the implications of having terms that are not adjacent.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in finding the common ratio when given the 7th and 26th terms of a GP, noting that they typically work with terms that are one apart.
  • Another participant suggests that the problem involves too many unknown variables, indicating that at least one of the variables, such as the first term or the number of terms, is necessary to solve for the common ratio.
  • A different participant explains the relationship between terms in a GP, proposing that the ratio between non-consecutive terms can be expressed in terms of the common ratio raised to a power.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to approach the problem, with multiple viewpoints on the necessary variables and methods to find the common ratio remaining present.

Contextual Notes

There are unresolved aspects regarding the dependence on the first term and the number of terms in the progression, which are not specified in the discussion.

Who May Find This Useful

Students and individuals studying geometric progressions, particularly those encountering problems involving non-consecutive terms.

Olly
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I am having toruble with my geometric progressions, in that i ahv ebeen given a question where i am given the 7th and 26th terms of a GP. I am required to find the ratio however, which i could do if i had the first term. Usually i can do this as they only give me gps that are one term apart, and i would divide the top by bottom (say Term6 = 3 and term7 = 4) and would end up with term1 = 3/4. How can i do this if the terms are as far apart as they are?

Welcoming any responses here :smile:
 
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Olly said:
I am having toruble with my geometric progressions, in that i ahv ebeen given a question where i am given the 7th and 26th terms of a GP. I am required to find the ratio however, which i could do if i had the first term. Usually i can do this as they only give me gps that are one term apart, and i would divide the top by bottom (say Term6 = 3 and term7 = 4) and would end up with term1 = 3/4. How can i do this if the terms are as far apart as they are?

Welcoming any responses here :smile:
i think you have too many variables such as a1 and n (the number of terms) that are unknown at least one of them are needed to solve for the quotinent.
 
You know that in a geometric progression, the next term's ratio with the previous is a constant; let's call it x; that is GP(n+1)/GP(n)=x.
But then we must have: GP(n+2)/GP(n)=(GP(n+2)/GP(n+1))*GP(n+1)/GP(n)=x^(2).
Did that help?
 
Thanks for the help, I've got it down pat now :) hope I am ready for maths test tomorrow :wink:
 

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