
#1
May2108, 10:33 AM

P: 228

Hi,
I had a query regarding the resistance from and I vs. V graph. Am i correct in thinking that the resistance is the recipricol of the GRADIENT at any given point? Or is the resistance simply the voltage through it at that point divided by the current? The two are obviously the same for a linear graph, but what about for nonlinear graphs? Thanks 



#2
May2108, 10:54 AM

P: 141

Since the gradient's defined as [tex]\frac{\delta{y}}{\delta{x}}[/tex], if your y axis represents voltage and your x axis represents current then the gradient will simply be the resistance. If your axes are reversed, then indeed it will be the reciprocal of the gradient.
In terms of nonlinear plots, the resistance will vary, and so taking the derivative of the graph at each point will give you the resistance at that point. 



#3
May2108, 10:58 AM

Emeritus
Sci Advisor
PF Gold
P: 9,789

[tex]I = \frac{1}{R}\cdot V[/tex] So yes, where the graph of I vs. V is linear then the gradient represents the resistance of the component. Components that exhibit linear I vs. V graphs are called Ohmic conductors, since they obey Ohm's law. NonOhmic conductors have nonlinear I vs. V plots and therefore do not obey Ohm's law. Needless to say, one cannot apply Ohm's law to nonohmic conductors and so it doesn't really make sense to say that a nonohmic conductor has a resistance R because it's value depends on the current and voltage through the component. 



#4
May2108, 12:16 PM

P: 228

Resistance from I vs. V graph
Thank you both for the help. So if I was given say a graph of a filament lamp for I vs. V, and asked to find the resistance at V=15V, would I finding the gradient of the graph, and then find the recipricol  would simply dividing the voltage by the current at that point give an incorrect answer?
Thanks 



#5
May2108, 01:01 PM

P: 83

R = V/I
just follow the graph across at 15 volts and find the Watts. then the volts by the watts. 



#6
May2108, 01:20 PM

HW Helper
P: 2,250

Hi nokia8650,
The slope of your curve (or 1/slope depending on what's on your yaxis) will not give the resistance except if the material obeys Ohms law. There is a quantity (differential resistance?) that is given by the slope of the curve, but again it's only equal to the resistance for Ohmic resistors. I believe the reason the slope is often used to calculate the resistance for ohmic resistors is that it minimizes the effects of experimental errors from any one measurement. 


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