|Jun10-08, 08:39 PM||#1|
Line Parallel to the Plane Equation (Final Exam Review)
1. The problem statement, all variables and given/known data
Explain why the line <x,y,z> = <3,1,4> + t<4,-5,2> is parallel to the plane with equation 2x + 2y +z = 7
2. Relevant equations
The normal vector of <x,y,z> [4,-5,2] and the plane equation 2x + 2y + z = 7
3. The attempt at a solution
Well, I'm trying to review for the final exam and I'm missing a crucial notes sheet.
So, I attempted to do the dot product of the normal vector and the plane equation vector which is:
4*2 + -5*2 + 1*2 = 0
However, that didn't add up to 7 which would mean == lines.
Though, I think by writing out the dot product I technically proved perpendicularity since plane equations are based off a vector and a point. Thus, making it perpendicular to that point.
So if two bits are perpendicular to the same point then they are parallel to each other.
Any help, would be much appreciated.
|Jun10-08, 09:57 PM||#2|
Yes, that's correct. If the line <x,y,z> = <3,1,4> + t<4,-5,2> is parallel to the plane, then its direction vector i.e. (4,-5,2) is perpendicular to the plane's normal vector.
|Jun10-08, 10:55 PM||#3|
Thank You So Much!
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