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Reaction mechanism |
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| Jun10-08, 11:37 PM | #1 |
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Reaction mechanism
1. The problem statement, all variables and given/known data
Draw a step-by-step mechanism using curly arrows for the following transformation. You do not have to worry about stereochemistry of the final product. 2. Relevant equations None 3. The attempt at a solution ![]() So the reaction is shown in the diagram in the first line. Here's what I did: 1. Electrons in the O-H bond move toward the oxygen, and hydrogen gets detached, forming a negative charge on the oxygen 2. pi electrons from the double bond attack a H+ (from the acid) and forms a carbocation 3. The negative oxygen's electrons are attracted to the carbocation centre and draws the molecule into a ring formation Does the mechanism make sense? Are there any other better ways of doing it? I know that there's another mechanism that involves the water molecule coming in, but I'm not sure about it. Thanks |
| Jun11-08, 01:57 AM | #2 |
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How likely is the presence of O- if it happens in the sulfuric acid?
Borek -- http://www.chembuddy.com http://www.ph-meter.info |
| Jun11-08, 11:09 AM | #3 |
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When I examine reaction mechanisms and am given a catalyst (like H2SO4 in this case), I try to use it in the first step. In this case H+ is the catalyst.
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| Jun11-08, 02:01 PM | #4 |
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Reaction mechanism
Hm... I attempted it again, using your suggestions, and here's my result.
![]() Does that look better? |
| Jun11-08, 02:08 PM | #5 |
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That's close. I wouldn't have lost the primary alcohol. If the alcohol were labelled (as O-18), the label would probably be found in the product.
Also, the sulfuric acid probably adds across the double bond in Markovnikov fashion. |
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