# Laplace transform question

by math_04
Tags: laplace, transform
 HW Helper P: 2,616 This is from my notes: In this case, the function should be u(t) - u(t-1). The Laplace transform you should be using is $$L[f(t-a)u(t-a)] = e^{-as}F(s) \ \mbox{where} \ F(s) = L[f(t)]$$ Note that u(t-a) = f(t-a)u(t-a) where f(t) = 1. f is a constant function. So you only need to find the laplace transform of 1 and add in the e^(-as) factor in front of it.