| Thread Closed |
Maximum Power Transferred |
Share Thread | Thread Tools |
| Jul10-08, 11:39 AM | #1 |
|
|
Maximum Power Transferred
1.
![]() 3. Pmax = Vth^2/4Rth so im guessing i treat R as the Rth and find Rth. to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth. my mesh analysis equations: Vx + 1 =0 -1 + i2 + 2Vx=0 therefore i2 = 3 2i3 + 1 =0 i3 =-1/2 i3 + i1 = i2 therefore i1 = 1/2 + 3 i1 = 7/2 Rth = (1)/(7/2) = 2/7 now to find Vth I used nodal analysis and mesh analysis both 1) (12-Vth)/2 = (Vth-2Vx)/1 2) -12 + Vx + Vth=0 Solving I found Vth = 15 V Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W CAN SOMEONE PLEASE CHECK THAT!!!!! thank you!!!!!!!!!!!!!!!!!!!!!! |
| Jul10-08, 09:53 PM | #2 |
|
Recognitions:
|
I didn't get Vth to be 15V. I got [tex]8\frac{4}{7}[/tex]. But I got the same value for Rth.
|
| Jul11-08, 09:28 AM | #3 |
|
|
are my equations right?
for solving Vth? 1) (12-Vth)/2 = (Vth-2Vx)/1 2) -12 + Vx + Vth=0 |
| Jul11-08, 09:33 AM | #4 |
|
|
Maximum Power Transferred
1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0 vx= 12 - vth (12-Vth)/2 = (Vth-2( 12 - vth))/1 12-Vth = 2Vth-48+4vth 12+48=vth+2vth+4vth 60=7vth okk ur right its 8.5ish ok kool |
| Thread Closed |
| Thread Tools | |
Similar Threads for: Maximum Power Transferred
|
||||
| Thread | Forum | Replies | ||
| maximum torque, maximum power | Introductory Physics Homework | 8 | ||
| Maximum Power Output of a Turbine | Engineering, Comp Sci, & Technology Homework | 3 | ||
| Energy transferred | Introductory Physics Homework | 1 | ||
| Maximum power/current for a battery? | Introductory Physics Homework | 3 | ||
| How exactly is heat transferred? | Classical Physics | 2 | ||