# Maximum Power Transferred

by salman213
Tags: maximum, power, transferred
 P: 303 1. 3. Pmax = Vth^2/4Rth so im guessing i treat R as the Rth and find Rth. to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth. my mesh analysis equations: Vx + 1 =0 -1 + i2 + 2Vx=0 therefore i2 = 3 2i3 + 1 =0 i3 =-1/2 i3 + i1 = i2 therefore i1 = 1/2 + 3 i1 = 7/2 Rth = (1)/(7/2) = 2/7 now to find Vth I used nodal analysis and mesh analysis both 1) (12-Vth)/2 = (Vth-2Vx)/1 2) -12 + Vx + Vth=0 Solving I found Vth = 15 V Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W CAN SOMEONE PLEASE CHECK THAT!!!!! thank you!!!!!!!!!!!!!!!!!!!!!!
 HW Helper P: 2,618 I didn't get Vth to be 15V. I got $$8\frac{4}{7}$$. But I got the same value for Rth.
 P: 303 are my equations right? for solving Vth? 1) (12-Vth)/2 = (Vth-2Vx)/1 2) -12 + Vx + Vth=0
P: 303

## Maximum Power Transferred

1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0

vx= 12 - vth

(12-Vth)/2 = (Vth-2( 12 - vth))/1

12-Vth = 2Vth-48+4vth

12+48=vth+2vth+4vth
60=7vth

okk ur right its 8.5ish

ok kool

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