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Maximum Power Transferred 
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#1
Jul1008, 11:39 AM

P: 303

1.
3. Pmax = Vth^2/4Rth so im guessing i treat R as the Rth and find Rth. to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth. my mesh analysis equations: Vx + 1 =0 1 + i2 + 2Vx=0 therefore i2 = 3 2i3 + 1 =0 i3 =1/2 i3 + i1 = i2 therefore i1 = 1/2 + 3 i1 = 7/2 Rth = (1)/(7/2) = 2/7 now to find Vth I used nodal analysis and mesh analysis both 1) (12Vth)/2 = (Vth2Vx)/1 2) 12 + Vx + Vth=0 Solving I found Vth = 15 V Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W CAN SOMEONE PLEASE CHECK THAT!!!!! thank you!!!!!!!!!!!!!!!!!!!!!! 


#2
Jul1008, 09:53 PM

HW Helper
P: 2,616

I didn't get Vth to be 15V. I got [tex]8\frac{4}{7}[/tex]. But I got the same value for Rth.



#3
Jul1108, 09:28 AM

P: 303

are my equations right?
for solving Vth? 1) (12Vth)/2 = (Vth2Vx)/1 2) 12 + Vx + Vth=0 


#4
Jul1108, 09:33 AM

P: 303

Maximum Power Transferred
1) (12Vth)/2 = (Vth2Vx)/1
2) 12 + Vx + Vth=0 vx= 12  vth (12Vth)/2 = (Vth2( 12  vth))/1 12Vth = 2Vth48+4vth 12+48=vth+2vth+4vth 60=7vth okk ur right its 8.5ish ok kool 


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