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Need help finding coefficient of kinetic friction 
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#1
Jul2308, 09:00 PM

P: 3

1. The problem statement, all variables and given/known data
A horizontal force of 150 N is used to push a 40.0 kg packing crate a distance of 6.00 m on a rough horizontal surface. If the crate moves at constant speed, find the coefficient of kinetic friction between the crate and the surface. 2. Relevant equations fK= coeff. of kin. friction X N Fy= mgy + normal force 3. The attempt at a solution I started by using Fy= mgy + N to be 0= 40 (9.8) (cos 0) + N and found N be 392. But now I'm not sure where to go from here to find the coefficient of kinetic friction. Can anyone help? 


#2
Jul2308, 09:12 PM

HW Helper
P: 6,202

Constant speed means the resultant force is zero....so what is the value of the frictional force?



#3
Jul2308, 09:15 PM

P: 3




#4
Jul2308, 09:17 PM

HW Helper
P: 6,202

Need help finding coefficient of kinetic friction
Yes that should be correct.



#5
Jul2308, 09:19 PM

P: 3

Thanks!



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