calculating work done on a truck by friction when a truck is pushing a car

kristy hardy

1. The problem statement, all variables and given/known data

A truck pushes a car by exerting a horizontal force of 500 N on it. A frictional force of 300N opposes the cars motion as it moves 4m. Calculate the work done on the truck.


2. Relevant equations

work = force x distance


3. The attempt at a solution

work done = 300N x 4 m = 1200J work right?

alphysicist

For constant forces, the work would be:

[tex]
W=F d\cos\theta
[/tex]

where [itex]\theta[/itex] is the angle between the force diretion and the displacement direction.


No, I believe that would be the magnitude of the work done by friction. Remember that if we want to calculate the work done on the truck, you have to use the forces that act on the truck.

danpos

My contribution: since the work done by resulting force on the body is the path integral along the path and this is a scalar (inner product from two vectors), is straightforward that the work of resulting force shall be the algebraic sum of work from each force acting on the considered body; in this way:

W = 500N x4 m - 300N x 4m = 800J

Danpos.

borgwal

Not correct: the 300N force is NOT the force acting on the truck.

borgwal

The title of your post asks a different question that your post itself: which one is the actual question? And, don't you have more info?