P: 142 1. The problem statement, all variables and given/known data The electron beam emerging from a certain high-energy electron accelerator has a circular cross section of radius 1.20 mm. (a) The beam current is 7.75 ľA. Find the current density in the beam assuming it is uniform throughout. correct check mark A/m2 (b) The speed of the electrons is so close to the speed of light that their speed can be taken as 300 Mm/s with negligible error. Find the electron density in the beam. correct check mark m-3 (c) Over what time interval does Avogadro's number of electrons emerge from the accelerator? s 2. Relevant equations $$J=I/A$$ $$I_{avg} = nqv_{d}A 3. The attempt at a solution Part a and b are straight forward. For part a I have: 1.71 A/m^2 For part b I have: 3.565 x 10^10 m^-3 I am having issues with part c. I know I need to figure out how many electrons are leaving the wire per second and then from there it should be a straight division problem using the 6.022 x 10^23 for Avogradro's number. HW Helper P: 5,341  Quote by Ithryndil 1. The problem statement, all variables and given/known data The electron beam emerging from a certain high-energy electron accelerator has a circular cross section of radius 1.20 mm. (a) The beam current is 7.75 ľA. Find the current density in the beam assuming it is uniform throughout. correct check mark A/m2 (b) The speed of the electrons is so close to the speed of light that their speed can be taken as 300 Mm/s with negligible error. Find the electron density in the beam. correct check mark m-3 (c) Over what time interval does Avogadro's number of electrons emerge from the accelerator? s 2. Relevant equations [tex]J=I/A$$ $$I_{avg} = nqv_{d}A$$ 3. The attempt at a solution Part a and b are straight forward. For part a I have: 1.71 A/m^2 For part b I have: 3.565 x 10^10 m^-3 I am having issues with part c. I know I need to figure out how many electrons are leaving the wire per second and then from there it should be a straight division problem using the 6.022 x 10^23 for Avogradro's number.