
#1
Sep2108, 03:38 AM

P: 37

Can somebody tell me what is the miller index for the tilted plane?
Is it (102) or (112)? Nothing seems to fit... I wonder if we can even describe it with miller index? Please download the picture here in pdf format: http://www.megaupload.com/?d=F8J344BH Thanks! 



#2
Sep2108, 03:39 AM

P: 37

or see the attached file if you can...




#3
Sep2108, 10:55 AM

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P: 2,532

Every plane has a Miller index. A common way to find the Miller index for a plane in a cubic system is to take the reciprocal of the axis intercepts and normalize the result so it contains only integers. Negative intercepts are treated by putting a bar over the number. For example, the yintercept in your figure is at 1.




#4
Sep2108, 12:57 PM

P: 37

miller index problem
thanks for the reply. But could you explain why is the y intercept for the triangular plane 1? it does not seem to intersect with the y axis?




#5
Sep2108, 03:52 PM

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P: 2,532

The plane continues on to infinity; if you follow the line in the yz plane, you'll see that it (and therefore the plane) intersects the yaxis at 1. Use the same approach for the other axes.




#6
Sep2108, 04:18 PM

P: 37

um..so are you saying that I can extend the vector so it eventually intersects with the yaxis?
so the miller index should be (112)? 



#7
Sep2108, 04:28 PM

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Yes; a [itex](1\bar 1 2)[/itex] plane (a member of the family of [itex]\{112\}[/itex] planes), with surface normal vector [itex][1\bar 1 2][/itex] (a member of the family of [itex]\langle 112\rangle[/itex] directions).




#8
Sep2108, 04:31 PM

P: 37

But, for example, this picture is also (1,1,2). so are they a family?




#9
Sep2108, 04:32 PM

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P: 2,532

More than another member of a family; that's the same plane.




#10
Sep2108, 04:36 PM

P: 37

ok. I think I am getting it, thanks a lot.



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