# Miller index problem

by Carolyn
Tags: index, miller
 P: 37 Can somebody tell me what is the miller index for the tilted plane? Is it (102) or (112)? Nothing seems to fit... I wonder if we can even describe it with miller index? Please download the picture here in pdf format: http://www.megaupload.com/?d=F8J344BH Thanks!
P: 37
or see the attached file if you can...
Attached Files
 miller index.pdf (19.1 KB, 58 views)
 Sci Advisor HW Helper PF Gold P: 2,532 Every plane has a Miller index. A common way to find the Miller index for a plane in a cubic system is to take the reciprocal of the axis intercepts and normalize the result so it contains only integers. Negative intercepts are treated by putting a bar over the number. For example, the y-intercept in your figure is at -1.
 P: 37 Miller index problem thanks for the reply. But could you explain why is the y intercept for the triangular plane -1? it does not seem to intersect with the y axis?
 Sci Advisor HW Helper PF Gold P: 2,532 The plane continues on to infinity; if you follow the line in the y-z plane, you'll see that it (and therefore the plane) intersects the y-axis at -1. Use the same approach for the other axes.
 P: 37 um..so are you saying that I can extend the vector so it eventually intersects with the y-axis? so the miller index should be (1-12)?
 Sci Advisor HW Helper PF Gold P: 2,532 Yes; a $(1\bar 1 2)$ plane (a member of the family of $\{112\}$ planes), with surface normal vector $[1\bar 1 2]$ (a member of the family of $\langle 112\rangle$ directions).
P: 37
But, for example, this picture is also (1,-1,2). so are they a family?
Attached Files
 miller.pdf (6.4 KB, 31 views)
 Sci Advisor HW Helper PF Gold P: 2,532 More than another member of a family; that's the same plane.
 P: 37 ok. I think I am getting it, thanks a lot.

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