Circuit/Resistors Problem


by hobo skinoski
Tags: circuit or resistors
hobo skinoski
hobo skinoski is offline
#1
Sep28-08, 08:33 PM
P: 2
Four resistors are connected to a battery as shown in the figure. The current in the battery is I, the battery emf is E, and the resistor values are R1 = R, R2 = 2R, R3 = 4R, and R4 = 3R.



-Determine the potential difference across each resistor in terms of E.
-Determine the current in each resistor in terms of I.
-In the limit that R3 → infinity, what are the new values of the current in each resistor in terms of I, the original current in the battery?


2. Relevant equations
V=IR
Rtotal=R1+R2+... (Series)
1/2Rtotal=1/R1 + 1/R2 ... (Parallel)


3. The attempt at a solution

I've tried a bunch of different combos, and i'm just wondering if there is some sort of way to do this.
Phys.Org News Partner Science news on Phys.org
Cougars' diverse diet helped them survive the Pleistocene mass extinction
Cyber risks can cause disruption on scale of 2008 crisis, study says
Mantis shrimp stronger than airplanes
hobo skinoski
hobo skinoski is offline
#2
Sep28-08, 09:32 PM
P: 2
hmm still trying. anyone out there?
Gear300
Gear300 is offline
#3
Sep28-08, 09:39 PM
P: 1,133
R2 and R3 are in series...we'll call their combination Rs. R4 is parallel to Rs...we'll call their combination Rp. R1 is in series with Rp...we'll call their combination Rt. Once you find Rt, the circuit should simply be a battery in series with a resistance of Rt. From this, you could find I1, the current running through the battery and R1. I1 splits into I2 and I3 at a junction. Note that the voltage between the junctions is the same per path.

LowlyPion
LowlyPion is offline
#4
Sep28-08, 10:03 PM
HW Helper
P: 5,346

Circuit/Resistors Problem


Quote Quote by hobo skinoski View Post
Four resistors are connected to a battery as shown in the figure. The current in the battery is I, the battery emf is E, and the resistor values are R1 = R, R2 = 2R, R3 = 4R, and R4 = 3R.


-Determine the potential difference across each resistor in terms of E.
-Determine the current in each resistor in terms of I.
-In the limit that R3 → infinity, what are the new values of the current in each resistor in terms of I, the original current in the battery?


2. Relevant equations
V=IR
Rtotal=R1+R2+... (Series)
1/2Rtotal=1/R1 + 1/R2 ... (Parallel)


3. The attempt at a solution

I've tried a bunch of different combos, and i'm just wondering if there is some sort of way to do this.
As Gear300 suggests you should first find the equivalent resistance of the entire network because that will yield the current from the E source. Then it is simply a matter of splitting the current between the legs as you go through the network.

The equivalent resistance R1234 is found by finding
R23 = R2 + R3
Then
R234 = R4 || R23
Then
R1234 = R1 + R234

Then I = E/R1234


Register to reply

Related Discussions
Finding current in a complex circuit with resistors Advanced Physics Homework 4
circuit with resistors in series and two power supplies Introductory Physics Homework 12
Finding the currents of four resistors in a circuit. Introductory Physics Homework 15
Resistors in a 555 Timer Circuit Engineering, Comp Sci, & Technology Homework 1
Simplyfing Parallel/Series Resistors in a Circuit Engineering, Comp Sci, & Technology Homework 4