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momentum transfer??? |
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| Oct2-08, 12:34 PM | #1 |
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momentum transfer???
when aircraft is in motion, it has momentum.
Since it has momentum, there is momentum transfer taking place between the aircraft and the air particles. During this momentum transfer what exactly is happening between the wings and fluid particles that are present right around wings? what are the consequences of gaining momentum from aircraft? as they gain momentum its obvious that they are set into motion relative to the aircraft. does this turbulent flow occurs due to this momentum transfer? if yes then what are the other things happening? |
| Oct3-08, 06:15 PM | #2 |
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I don't understand all of your question because I think some of it does not make any sense. So, I'll just say what's going on:
The fluid particles right at the wing are stagnant (stationary). There is a boundary layer around the wing that builds up as the velocity goes from zero, all the way up to whatever the local steady state velocity is at that point along the wing. The fluid particles approaching the wing at the free stream velocity [tex]V_\infty[/tex] has some momentum. When they approach the wing they can go either above the wing, or below the wing. If they go below the wing, they are going to be deflected downward. This changes the momentum of the particle to a new direction, and as we know a change in momentum produces a force via newtons 3rd law equal and opposite on the wing. If, on the other hand, the particle of air goes above the wing, it will become accelerated and by bernoullis equation will reduce the static pressure at the top surface of the wing. So the wing has more pressure at the bottom, less pressure at the top causing lift. As the same time, it's also turning the flow downwards which also produces lift. To say that it's bernoulli or flow turning that causes lift really makes no sense becasue the two go hand in hand. You can't do one without the other. |
| Oct4-08, 09:34 AM | #3 |
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| Oct5-08, 12:03 AM | #4 |
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momentum transfer???
hey Cyrus, m sorry, m German so i have problem with my English. I knew i didn't put my question in a right way. But Lurch got it what i meant to ask.
thank you guys for replying. |
| Oct5-08, 12:26 AM | #5 |
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i hope you got my question. god i hate my english. |
| Oct5-08, 01:21 AM | #6 |
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| Oct5-08, 01:49 PM | #7 |
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In fact, your two questions are actually two forms of the same question. That should be encouraging; you only need to find half as many answers as you thought you did!
It is true that if you are standing on the wing of the aircraft, you see air particles colliding with the leading edge of the wing, gaining some slight lateral movement, but mostly moving toward the trailing edge. The situation is very similar to what you would experience if you are standing on the hood of a moving automobile. It is the motion of the air as seen from the vehicle's point of view. However, you see a very different situation if you are standing near a roadway when an automobile passes by. Assuming there is no wind, you will see the air particles standing still. Then, as the auto passes by, you would see those air particles get disturbed in a very chaotic fashion. But then, eventually, one certain direction would be seen to dominate; the same direction that the auto was moving. The same happens with the aircraft. The air gets jumbled up in a way that might look random at first, but over all, it ends up beign "pulled along" or sucked after the aircraft. So, compared to the sarounding air, these particles start out stationary, and then (through transfer of momentum) are set in motion in the direction the plane is moving. So the difference between their velocity and the plane's velocity has decreased, while the difference between their velocity and the velocity of the sarounding air has increased (from "zero" to "something"). BTW: I think your english is pretty good. Certainly a lot better than my German! |
| Oct5-08, 11:41 PM | #8 |
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thank you Lurch, i got it. thank you so much.
thanks all of of you guys. |
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