Find the Horizontal Tangent of f(x)=x^2 + 4x - 1

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    Horizontal Tangent
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SUMMARY

The horizontal tangent of the function f(x) = x^2 + 4x - 1 occurs at the point where the derivative equals zero. The derivative of the function, f'(x) = 2x + 4, is set to zero, leading to the solution x = -2. This indicates that the tangent line is horizontal at the point (-2, f(-2)), which can be calculated as f(-2) = 1. Therefore, the horizontal tangent is found at the coordinates (-2, 1).

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PrudensOptimus
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At what point is the tangent to f(x)=x^2 + 4x - 1 horizontal?

How do you do that? I think it's asking me at what point is x = 0, or undefined, right??
 
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Hint:

What is the unique feature about the equation of a horizontal line?
How does that relate to tangent lines?
 
Last edited:
Horizontal tangent is where derivative=0, that is x=-2.
 

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