
#1
Dec108, 09:00 PM

P: 7

1. The problem statement, all variables and given/known data
A proton (m=1.67x10^27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E. 2. Relevant equations F_{E}=qE F_{g}=mg 3. The attempt at a solution F_{G} = mg F_{G} = (1.67x10^{27})(9.8) F_{G} = 1.64 x 10^{26} Since the force on the proton due to the E field is equal and opposite, then: F_{E}=qE F_{E} / q= E (1.64x10^{26}) / (1.6x10^{19}) = E 1.04x10^{9} = E Is my work correct? 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 



#2
Dec108, 09:42 PM

HW Helper
P: 5,346





#3
Dec108, 09:44 PM

P: 7

Probably not, but does the way I reached my answer make sense?




#4
Dec208, 01:24 AM

HW Helper
P: 2,618

Uniform Electric Fields
Yes the steps are correct, just a calculation error.



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