Uniform Electric Fields


by EtherMD
Tags: electric, fields, uniform
EtherMD
EtherMD is offline
#1
Dec1-08, 09:00 PM
P: 7
1. The problem statement, all variables and given/known data
A proton (m=1.67x10^-27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E.


2. Relevant equations
FE=|q|E
Fg=mg


3. The attempt at a solution
FG = mg
FG = (1.67x10-27)(9.8)
FG = 1.64 x 10-26

Since the force on the proton due to the E field is equal and opposite, then:
FE=|q|E
FE / q= E
(1.64x10-26) / (1.6x10-19) = E
1.04x10-9 = E


Is my work correct?
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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LowlyPion
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#2
Dec1-08, 09:42 PM
HW Helper
P: 5,346
Quote Quote by EtherMD View Post
Since the force on the proton due to the E field is equal and opposite, then:
FE=|q|E
FE / q= E
(1.64x10-26) / (1.6x10-19) = E
1.04x10-9 = E
Have you handled your exponents correctly?
EtherMD
EtherMD is offline
#3
Dec1-08, 09:44 PM
P: 7
Probably not, but does the way I reached my answer make sense?

Defennder
Defennder is offline
#4
Dec2-08, 01:24 AM
HW Helper
P: 2,618

Uniform Electric Fields


Yes the steps are correct, just a calculation error.


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