## Uniform Electric Fields

1. The problem statement, all variables and given/known data
A proton (m=1.67x10^-27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E.

2. Relevant equations
FE=|q|E
Fg=mg

3. The attempt at a solution
FG = mg
FG = (1.67x10-27)(9.8)
FG = 1.64 x 10-26

Since the force on the proton due to the E field is equal and opposite, then:
FE=|q|E
FE / q= E
(1.64x10-26) / (1.6x10-19) = E
1.04x10-9 = E

Is my work correct?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
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Recognitions:
Homework Help
 Quote by EtherMD Since the force on the proton due to the E field is equal and opposite, then: FE=|q|E FE / q= E (1.64x10-26) / (1.6x10-19) = E 1.04x10-9 = E
Have you handled your exponents correctly?
 Probably not, but does the way I reached my answer make sense?

Recognitions:
Homework Help

## Uniform Electric Fields

Yes the steps are correct, just a calculation error.

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