How Do You Calculate the Charge on the Inner Sphere Using Gauss's Law?

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SUMMARY

The charge on the inner sphere, calculated using Gauss's Law, is 2.89e+13 nC. The radial electric field at a distance of 3.125 cm is given as 7.366e+04 N/C. The calculation involves determining the electric flux through the Gaussian surface, which is derived from the electric field and the surface area of the inner sphere. The formula used is Q = ε0 * electric flux, where ε0 is the permittivity of free space.

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frogstomp_theory
Two charged concentric metal spheres have radii of 3.000 cm and 3.500 cm. Calculate the charge in nC on the inner sphere if the radial electric field at a radial distance 3.125 cm is 7.366e+04 N/C.

I tried using Gausses law of EA = Q/e0 then after getting
Q I would take the average charge per area. Then I would simply enter into the equation Q=o(greek letter)A the area of the inner sphere, but that's wrong:frown: any suggestions?

I've been having trouble with magnetism so any help is appreciated, thanks.
 
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Hi, and welcome to PF.

Originally posted by frogstomp_theory
I tried using Gausses law of EA = Q/e0 then after getting
Q I would take the average charge per area. Then I would simply enter into the equation Q=o(greek letter)A the area of the inner sphere[/color], but that's wrong:frown: any suggestions?

I've highlighted your mistake[/color] above. You should be using the area of the Gaussian surface, not the inner sphere.

I've been having trouble with magnetism so any help is appreciated, thanks.

Actually, this is electrostatics and has nothing to do with magnetism.
 


Based on the given information, we can use Gauss's law to calculate the charge on the inner sphere. Gauss's law states that the electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space (ε0). In this case, the inner sphere acts as the closed surface, with the radial distance of 3.125 cm being the radius of the surface.

First, we need to calculate the electric flux through the surface. The electric field is given as 7.366e+04 N/C, and the area of the inner sphere can be calculated using the formula for the surface area of a sphere (4πr^2). Plugging in the values, we get the electric flux to be 2.89e+07 Nm^2/C.

Next, we can rearrange Gauss's law to solve for the charge enclosed by the inner sphere. This gives us Q = ε0 * electric flux. Plugging in the values, we get the charge on the inner sphere to be 2.89e+04 C. However, the given unit for charge is in nanocoulombs (nC), so we need to convert it. 1 C = 1e+9 nC, so the charge on the inner sphere is 2.89e+13 nC.

In conclusion, the charge on the inner sphere is 2.89e+13 nC. It is important to double check the units and make sure they are consistent throughout the calculation. Hope this helps!
 

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