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Limit of x^x^x as x->0 from right

by emilkh
Tags: limit, x>0
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emilkh
#1
Dec6-08, 08:28 PM
P: 7
Any ideas?
lim XXX
x-> 0+

I know how to do x^x:
lim XX = lim ex * ln x = e0 = 0
lim x * ln x = lim ln x / (1/x) = lim (1/x) / (-1/x2) = lim -x = 0
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mutton
#2
Dec6-08, 10:08 PM
P: 179
Now x^x is the exponent and x is the base, so do exactly as you just explained.
emilkh
#3
Dec6-08, 10:12 PM
P: 7
Could you elaborate more? I alredy tried this method and got stuck with
lim (ln x) * (x^x), i could not solve it

Hurkyl
#4
Dec6-08, 10:15 PM
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Limit of x^x^x as x->0 from right

Quote Quote by emilkh View Post
Could you elaborate more? I alredy tried this method and got stuck with
lim (ln x) * (x^x), i could not solve it
Why are you stuck? You already said you knew what to do with x^x....
emilkh
#5
Dec6-08, 10:24 PM
P: 7
lim ln x * (x^x) = lim ln x * lim x ^ x = (- infinity) * 0 = 0 as X -> 0+

So you want to tell me that lim (X^x^x) = lim ex^x *ln x = e^0 = 1?

The limit suppose to be 0, .000001 ^ ( .000001 ^ .000001 ) = very very very small number (checked with calculator)
mutton
#6
Dec6-08, 10:27 PM
P: 179
Quote Quote by emilkh View Post
lim ln x * (x^x) = lim ln x * lim x ^ x = (- infinity) * 0 = 0 as X -> 0+
Be careful; [tex]- \infty \cdot 0[/tex] is indeterminate.

Edit: I see, nevermind.
emilkh
#7
Dec6-08, 10:31 PM
P: 7
Quote Quote by mutton View Post
Be careful; [tex]- \infty \cdot 0[/tex] is indeterminate.
Well great! This is where I am stuck.

lim ln x * x was solved by switching it to lim ln x / (1/x) and taking derivatives, with lim ln x * x/x it's not gonna work
poutsos.A
#8
Dec6-08, 10:39 PM
P: 101
Quote Quote by emilkh View Post
Any ideas?
lim XXX
x-> 0+

I know how to do x^x:
lim XX = lim ex * ln x = e0 = 0
lim x * ln x = lim ln x / (1/x) = lim (1/x) / (-1/x2) = lim -x = 0
e0 is not =0, but...........1.............. here is your mistake ,

hence ......limx^x=1 as x tends to 0 from the right

And lim (ln x) * lim x^x = infinity multiplied by 1 and NOT by 0
emilkh
#9
Dec6-08, 10:43 PM
P: 7
[edited for content], in my solutions it was 1, but somehow I copied formula wrong and the whole time assumes lim x^x = 0. I spend way too much time studying for finals.... gotta take break


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