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Quantum Mechanics: Expectation values |
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| Dec22-08, 07:40 PM | #1 |
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Quantum Mechanics: Expectation values
1. The problem statement, all variables and given/known data
I need to find the expectation value for E but I don't know how b acts on the vacuum state. 2. Relevant equations [tex] b = \int dt \phi^{*}(t) \hat{{\cal E}}_{in}(t) [/tex] [tex] | \psi(t)\rangle = b^\dagger| 0\rangle [/tex] 3. The attempt at a solution [tex] \langle \psi(t) | \hat{{\cal E}}^\dagger\hat{{\cal E}}| \psi(t)\rangle = [/tex] |
| Dec23-08, 12:59 PM | #2 |
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What did I not make clear?
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| Dec23-08, 08:08 PM | #3 |
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Recognitions:
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| Dec23-08, 09:49 PM | #4 |
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Quantum Mechanics: Expectation values
This represents the single photon output level and I'm supposed to determine the
mean value and standard deviation of the single photon amplitude. [tex] \hat{{\cal E}} = e^{-\kappa \tau}+ e^{-\kappa t}\int^{t}_{0}e^{\kappa \tau} \sqrt{2\kappa}\, \hat{{\cal E}}_{in}(\tau)dt [/tex] I'm integrating with respect to time. [tex] {\cal E} [/tex]is an operator in Heisenberg picture. b^+ creates a photon in the temporal mode [tex]\phi(t)[/tex] Does that make sense? |
| Dec24-08, 05:17 PM | #5 |
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Recognitions:
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Sorry, it does not make sense to me. Perhaps someone else will be able to help.
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