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integration of irrational function |
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| Jun7-03, 11:39 PM | #1 |
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integration of irrational function
Here's the question that I got stuck:
[inte]sqrt[x/(a-x)] dx ......................................(*) I tried to use the following substitution u=sqrt[x/(a-x)] and .........................................(1) dx = 2u(1-a)/(1+u2)2 du................(2) sub (1) and (2) into (*), after a few steps, I got (2-2a)[inte]du/(1+u2) - 2(1-a)[inte]du/(u2+1)2 The answer derived from the first part, (2-2a)[inte]du/(1+u2), contains tan -1 but the model answer of this question is -[squ](ax-x2) + a/2sin-1[(2x+a)/a] + C For the second part, I let u = tan θ and got a strange expression. Is my approach correct and is the final answer obtained from the above method differs the model answer only by the constant of integration ? Or am I using a wrong substitution? |
| Jun8-03, 09:17 AM | #2 |
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Check your work on your substitution.
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| Jun9-03, 07:00 AM | #3 |
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u=sqrt[x/(a-x)]
dx = 2au/(1+u2)2 du thanks |
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