The discussion focuses on plotting sin(t) against cos(t) using MATLAB's linspace function, specifically for values of t ranging from -π to π. The user implemented the code t=linspace(-pi,pi) and plot(cos(t),sin(t)), resulting in a plot that correctly represents a circle, as both sin(t) and cos(t) yield values within the interval [-1, 1]. The confusion arose from the expectation of a different visual representation, but the output is indeed accurate for the specified mathematical functions.
Students, educators, and anyone interested in MATLAB programming, particularly those working with trigonometric functions and graphical representations in mathematics.
magma_saber said:Homework Statement
I have to make a plot with sin(t) (y values) vs cos(t) (x values). The values of t should be between -pi and pi. I'm supposed to use linspace.
Homework Equations
The Attempt at a Solution
i used these lines:
t=linspace(-pi,pi)
plot(cos(t),sin(t))
when i tried it out, the plot came out like this:
it shouldn't look like this should it? its only showing the plot go from -1 to 1.