# Point on a Curve

by jgens
Tags: curve, point
 P: 1,391 1. The problem statement, all variables and given/known data A particle moves along a path described by y = 4 - x^2. At what point along the curve are x and y changing at the same rate 2. Relevant equations Simple equations regarding derivatives. 3. The attempt at a solution It's been a while before I've done any related rates problems, could someone please let me know if this is correct: Since, x and y must be changing at the same rate (presumably with respect to time) x' = y' and y' = -2xx'. Therefore, -2x = 1 and x = -1/2. Placing my x value into the original equation yields 15/4. Hence, the point is (-1/2, 15/4). Thanks.
 P: 36 SEEMS correct...
 HW Helper Sci Advisor Thanks P: 24,461 Of course, it's right. What could go wrong?
P: 1,391

## Point on a Curve

Plenty, I could have made an incorrect assumption ultimately leading to false conclusions.
 PF Patron HW Helper Sci Advisor P: 4,755 Good answer but you do not need to assume that x and y are varying wrt an external parameter. The derivative y'(x) = dy/dx of y wrt x expresses the instantaneous rate of change of y wrt a change in x. The points where y and x are changing at the same rate are those where y'(x)=1.

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