Point on a Curve

by jgens
Tags: curve, point
jgens is offline
Jan20-09, 10:27 PM
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1. The problem statement, all variables and given/known data

A particle moves along a path described by y = 4 - x^2. At what point along the curve are x and y changing at the same rate

2. Relevant equations

Simple equations regarding derivatives.

3. The attempt at a solution

It's been a while before I've done any related rates problems, could someone please let me know if this is correct:

Since, x and y must be changing at the same rate (presumably with respect to time) x' = y' and y' = -2xx'. Therefore, -2x = 1 and x = -1/2. Placing my x value into the original equation yields 15/4. Hence, the point is (-1/2, 15/4).

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mrdoe is offline
Jan20-09, 10:37 PM
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SEEMS correct...
Dick is offline
Jan20-09, 11:08 PM
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Of course, it's right. What could go wrong?

jgens is offline
Jan20-09, 11:13 PM
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Point on a Curve

Plenty, I could have made an incorrect assumption ultimately leading to false conclusions.
quasar987 is online now
Jan20-09, 11:15 PM
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Good answer but you do not need to assume that x and y are varying wrt an external parameter. The derivative y'(x) = dy/dx of y wrt x expresses the instantaneous rate of change of y wrt a change in x.

The points where y and x are changing at the same rate are those where y'(x)=1.

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