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Finding x and y components

by spokorne
Tags: components
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spokorne
#1
Jan27-09, 07:34 PM
P: 6
I've been stuck on this problem for too long and need help. Please explain the answer if possible.

F1 has a magnitude of 8.80 n and is directed at an angle of [tex]\alpha[/tex]= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of [tex]\beta[/tex] = 53.3 below the negative x axis in the third quadrant.


What is the x component Fx of the resultant force?

What is the y component Fy of the resultant force?

What is the magnitude F of the resultant force?

What is the angle [tex]\gamma[/tex] that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis.
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LowlyPion
#2
Jan27-09, 08:58 PM
HW Helper
P: 5,343
Welcome to PF.

What have you attempted?
spokorne
#3
Jan27-09, 09:00 PM
P: 6
i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right

LowlyPion
#4
Jan27-09, 09:02 PM
HW Helper
P: 5,343
Finding x and y components

Maybe if you calculated the x,y components of the vectors it would be a little easier?
spokorne
#5
Jan27-09, 09:06 PM
P: 6
how do you go about doing that?
LowlyPion
#6
Jan27-09, 09:10 PM
HW Helper
P: 5,343
The dog on a leash is an example at the bottom of this link:
http://www.glenbrook.k12.il.us/GBSSC...ors/u3l1e.html
spokorne
#7
Jan27-09, 09:19 PM
P: 6
That's what I did previously and then then i found the difference in the two and it was incorrect
LowlyPion
#8
Jan27-09, 09:22 PM
HW Helper
P: 5,343
I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components.

After you have added them then you use what Pythagoras taught.


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