
#1
Jan2709, 07:34 PM

P: 6

I've been stuck on this problem for too long and need help. Please explain the answer if possible.
F1 has a magnitude of 8.80 n and is directed at an angle of [tex]\alpha[/tex]= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of [tex]\beta[/tex] = 53.3 below the negative x axis in the third quadrant. What is the x component Fx of the resultant force? What is the y component Fy of the resultant force? What is the magnitude F of the resultant force? What is the angle [tex]\gamma[/tex] that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis. 



#2
Jan2709, 08:58 PM

HW Helper
P: 5,346

Welcome to PF.
What have you attempted? 



#3
Jan2709, 09:00 PM

P: 6

i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right




#4
Jan2709, 09:02 PM

HW Helper
P: 5,346

Finding x and y components
Maybe if you calculated the x,y components of the vectors it would be a little easier?




#5
Jan2709, 09:06 PM

P: 6

how do you go about doing that?




#6
Jan2709, 09:10 PM

HW Helper
P: 5,346

The dog on a leash is an example at the bottom of this link:
http://www.glenbrook.k12.il.us/GBSSC...ors/u3l1e.html 



#7
Jan2709, 09:19 PM

P: 6

That's what I did previously and then then i found the difference in the two and it was incorrect




#8
Jan2709, 09:22 PM

HW Helper
P: 5,346

I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components.
After you have added them then you use what Pythagoras taught. 


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