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Why does a universe with a spherical geometry have to be finite? 
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#1
Feb1709, 06:29 PM

P: 65

I have read that "A universe with a spherical geometry is called a closed universe because a universe with this geometry must be finite" but even after looking up different sources i cannot find an decent explanation of it is finite. I know that a flat universe is just an unbound 3d grid that goes on forever and is therefore infinite, a hyperbolic universe is also infinite because it stretches on forever (i can't really visualize this).
I can't understand a why a spherical universe has to be finite. Would appreciate it if someone could shed some light on this for me. 


#2
Feb1709, 07:34 PM

Astronomy
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Let's imagine a onedimensional universe that has the geometry of a ring. A circle. I think this must be finite, length is the appropriate measure in one dimension, I think any particiular ring universe that you choose must have some finite length (called the circumference). Do you agree? If not, please show me an example of some particular ring with infinite circumference. ============ After that, let's talk about a 2D universe that is the surface of a ball. I think any example of such a thing must have a finite area (the appropriate measure for a 2D sphere surface). Do you agree, or can you describe some definite fixed sphere with infinite surface area? 


#3
Feb1709, 07:56 PM

P: 65

Ok i think what you are saying is that a 1D ring universe is finite because if you go all the way around the ring you end up where you started after traveling some finite distance, ie bound to the ring?
What I don't understand is why definition of the ring universe doesn't explicitly state that the ring has to have a finite diameter and therefore finite circumference? Or is that just implicit because it uses a bound shape, the circle? I guess my example of a ring with infinite circumference is one with infinite area and diameter. 


#4
Feb1709, 08:12 PM

P: 1,822

Why does a universe with a spherical geometry have to be finite?
When you read about a universe with a spherical geometry they are referring to a universe that obeys the geometry of a sphere, albeit a four dimensional sphere. The sum of the angles of triangles add up to more than 180 deg and there are no parallel lines. This would be a finite yet unbounded universe.
There is another kind of spherical universe discussed by Einstein that is infinite yet bounded. If as we look into space we see that the farther away a galaxy is the faster it is receding from us, and if the universe is old enough, there would be galaxies receding at velocities approaching the speed of light. Because they would be contracted in the direction they are receding, an infinite number of them could be squeezed into the space at the limit of the universe. So far, the available evidence about our universe doesn't fit either of these descriptions. 


#5
Feb1709, 08:22 PM

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#6
Feb1709, 10:30 PM

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Most of the galaxies which we now observe are receding at rates greater than the speed of light. Anything with a redshift bigger than 1.4. And there is a whole lot of stuff visible with redshift > 1.4. It doesn't cause any sort of "contraction". You may be thinking of the special relativity speed limit which doesn't apply to recession rates. There is a good SciAm article called "Misconceptions about the Big Bang". I have a link to it in my signature (small print at bottom of post). It is the princeton.edu link. The author is Charles Lineweaver (a world class cosmologist by the way ) 


#7
Feb1809, 09:21 AM

P: 1,822

Marcus, what you are saying is true. This theory is not my theory. I remember studying it many years ago in college and spent a little time searching for it but couldn't find it. I didn't intend to imply that that theory represents our current understanding of cosmology, in fact I think I said that.



#8
Feb1809, 12:35 PM

P: 177

how about a fractal surface? 


#9
Feb1909, 12:52 AM

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I was talking about the 2D surface of a 3D ball, something with a definite geometry. If you want to talk about some other geometric object, some different surface, you could define it. 


#10
Feb1909, 03:06 AM

P: 499

http://www.astro.ucla.edu/~wright/cosmo_02.htm#DH 


#11
Feb1909, 08:24 AM

P: 177

one thing I kind of take issue with and it's probably due to a lack of understanding on my part. It has been said that in postivly curved space there can be no parralel lines, that they would eventually intersect. Yet I can draw paralel non intersecting lines all the way around a globe. Actually I understand the concept, I'm just being nitpicky, I think the globe and poles analogy is useful only to a point. like the baloon analogy. but I like a previous posters comment about a circle or sphere with infinite diameter. That would be as easy to imagine as an infinite 2d plane. 'edit'.. another quick thought. since the circumference of a circle is calculated based on PI and since PI has infinite decimal fraction then is the circumference of a circle really finite? Hope all that's not too off topic. 


#12
Feb1909, 09:21 AM

P: 2,456

Well, the question is much deeper I believe
We observe a spacetime curvature, but curvature does not define the tolopogy of the space. For example, we can not say if we are inside a sphere or semisphere (halfsphere, not sure what term is correct. It has the same curvature as sphere everywhere, but its volume is 1/2 of the sphere) . 


#13
Feb1909, 10:07 AM

P: 65

Back on topic... A euclidean (3D uniform grid) universe can become infinite but only after being allowed an infinite amount of time to expand. Why couldn't a spherical (3d universe bound to the 4D equivalent of a sphere?) universe become infinite after being allowed to expand forever? I think i might be going round in circles (no pun intended) in my head trying to understand this concept. 


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