Find the Probability of Winning a Coin Toss Game | GRE Math Practice

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Discussion Overview

The discussion revolves around calculating the probability of winning a coin toss game where two players take turns tossing a fair coin, with the winner being the first to toss a head. The focus is on determining the correct probability from a set of multiple-choice options in the context of GRE Math preparation.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests that the first player has an advantage, ruling out options (A), (B), and (C).
  • The same participant presents sequences of outcomes that lead to a win for the first player and proposes that the probability can be expressed as an infinite sum.
  • The calculated probability of the first player winning is stated to be 2/3, corresponding to option (D).
  • Another participant reiterates the same reasoning and adds that the derived sum is less than 3/4, suggesting further elimination of options.
  • There is mention of a similar question being posted in another forum, indicating that the discussion may not be unique.

Areas of Agreement / Disagreement

Participants generally agree on the advantage of the first player and the calculation method, but there is no consensus on the final answer as the discussion includes multiple interpretations of the probability calculation.

Contextual Notes

The discussion does not resolve the mathematical steps involved in the infinite sum or the implications of the sequences presented. There may be assumptions regarding the fairness of the coin and the independence of tosses that are not explicitly stated.

lhuyvn
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Hi members,
I have traveled this forum sometimes, But this is my first question. I hope to get your help so that I can prepare better for my GRE Math test.

Following is my question.

In a game two players take turns tossing a fair coin; the winner is the firt one to toss a head. The probability that the player who makes the first toss wins the game is:
A)1/4
B)1/3
C)1/2
D)2/3
E)3/4

Thanks in advance.
LuuTruongHuy
 
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It has to be an advantage to make the first toss, so you can immediately rule out (A), (B), and (C).

Here are the sequences that give the win to the first player:

H
TTH
TTTTH
TTTTTTH
TTTTTTTTH
...

Just add the probabilities for the sequences above:

Probability of first player winning = (1/2) + (1/2)^3 + (1/2)^5 + ...

The infinite sum works out to 2/3, so (D) is the right answer.
 
Janitor said:
It has to be an advantage to make the first toss, so you can immediately rule out (A), (B), and (C).

Here are the sequences that give the win to the first player:

H
TTH
TTTTH
TTTTTTH
TTTTTTTTH
...

Just add the probabilities for the sequences above:

Probability of first player winning = (1/2) + (1/2)^3 + (1/2)^5 + ...

The infinite sum works out to 2/3, so (D) is the right answer.

Also, this sum is clearly smaller than (1/2) + [(1/2)^3 +(1/2)^4 + (1/2)^5 +...]

and the number inside [ ] is clearly (1/2)^2 or 1/4.

So the answer would have to be less that 3/4.

This variation to the approach doesn't save a whole lot of time - maybe half a minute at most - and it may leave you feeling uncertain about picking a choice without seeing any direct evidence for its correctness.

Anyways, just thought I'd drop it in as a useful elimination trick.
 
Hi

Apparently, the same question was posted in the general math forum...so we replied to it about an hour back. (I've changed the equations a bit though they are essentially the same things).
 

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