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gravitational constanT G -- HELP! |
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| Jun6-04, 01:39 PM | #1 |
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gravitational constanT G -- HELP! ok, right now I'm working on a physics project :) satelite motion around earth...I managed to create a program that simulates all that stuff...but I don't quite like my G constant! In my program I want to recreate moon and earth relationship! so scale looks this way: 1pixel = 1829773.7957659496946338217168068 meters so now I want my G number to be written in pixels, I know it's m*m*m/kg * s * s so, I can't make up my mind, how to write that in pixels...:) any help appreciated :) |
| Jun6-04, 02:29 PM | #2 |
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You can do it by dimensional analysis. Just treat a pixel as just another unit of length, as if you were going to convert G from SI units to British units.
First, let b = 1829773.7957659496946338217168068, where your conversion factor is "b meters per pixel." Additionally, I'm going to write G = 6.673*10^-11 m^3/(kg*s^2) here, but you should use a value to however many decimals you wish. So: [tex] \newcommand{\unit}[1]{\mathrel{\mathrm{#1}}} G = \frac{6.673\times 10^{-11}\unit{m^3}}{\unit{kg\cdot s^2}}\cdot \frac{\unit{pixel^3}}{(b\unit{m})^3} [/tex] Therefore, your new value of the gravitational constant is: [tex] \newcommand{\unit}[1]{\mathrel{\mathrm{#1}}} G = \frac{6.673\times 10^{-11}\unit{pixel^3}}{b^3\unit{kg\cdot s^2}} \approx \frac{1.089\times 10^{-29}\unit{pixel^3}}{\unit{kg\cdot s^2}} [/tex] To make a long story short, divide by 1829773.7957659496946338217168068^3. |
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