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gravitational constanT G -- HELP!

 
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Jun6-04, 01:39 PM   #1
 
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gravitational constanT G -- HELP!




ok, right now I'm working on a physics project :) satelite motion around earth...I managed to create a program that simulates all that stuff...but I don't quite like my G constant!

In my program I want to recreate moon and earth relationship!

so scale looks this way:
1pixel = 1829773.7957659496946338217168068 meters

so now I want my G number to be written in pixels, I know it's m*m*m/kg * s * s

so, I can't make up my mind, how to write that in pixels...:)

any help appreciated :)
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Jun6-04, 02:29 PM   #2
 
You can do it by dimensional analysis. Just treat a pixel as just another unit of length, as if you were going to convert G from SI units to British units.

First, let b = 1829773.7957659496946338217168068, where your conversion factor is "b meters per pixel." Additionally, I'm going to write G = 6.673*10^-11 m^3/(kg*s^2) here, but you should use a value to however many decimals you wish.

So:

[tex]
\newcommand{\unit}[1]{\mathrel{\mathrm{#1}}}
G = \frac{6.673\times 10^{-11}\unit{m^3}}{\unit{kg\cdot s^2}}\cdot
\frac{\unit{pixel^3}}{(b\unit{m})^3}
[/tex]

Therefore, your new value of the gravitational constant is:

[tex]
\newcommand{\unit}[1]{\mathrel{\mathrm{#1}}}
G = \frac{6.673\times 10^{-11}\unit{pixel^3}}{b^3\unit{kg\cdot s^2}}
\approx \frac{1.089\times 10^{-29}\unit{pixel^3}}{\unit{kg\cdot s^2}}
[/tex]

To make a long story short, divide by 1829773.7957659496946338217168068^3.
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