Lenses Question


by Grekory
Tags: lenses
Grekory
Grekory is offline
#1
Mar1-09, 07:25 AM
P: 2
When i'm given do, ho, and hi. How would i solve for di
Normally i would do -di/do = hi/ho and cross-multiply but i'm not sure how the negative comes into effect.

do = object distance
di = image distance
ho = object height
hi = image height



If...

ho = 3cm
hi = 4cm
do = 5cm

What would be di?

Thanks
Phys.Org News Partner Science news on Phys.org
Review: With Galaxy S5, Samsung proves less can be more
Making graphene in your kitchen
Study casts doubt on climate benefit of biofuels from corn residue
Doc Al
Doc Al is offline
#2
Mar1-09, 07:36 AM
Mentor
Doc Al's Avatar
P: 40,889
Please provide the complete statement of the problem you are trying to solve. (I presume that a negative image height means that the image is inverted.)
Grekory
Grekory is offline
#3
Mar1-09, 07:38 AM
P: 2
It's just made up values and i want to know how i would solve for di. The negative in the formula confuses me

Doc Al
Doc Al is offline
#4
Mar1-09, 07:59 AM
Mentor
Doc Al's Avatar
P: 40,889

Lenses Question


Start with:
-di/do = hi/ho

You can solve for di by cross-multiplying if you like, or just multiply both sides by -do. As I said before, a negative value for di just means that the image is inverted. (Real images are inverted.)


Register to reply

Related Discussions
lenses question Introductory Physics Homework 8
Lenses Question Introductory Physics Homework 0
Lenses Question help! Introductory Physics Homework 2
question about sound and lenses General Physics 0
Question about Convex lenses General Physics 6