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Show that perfect a perfect reflector is a conic section with Fermat's principle

 
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Mar19-09, 01:42 PM   #1
 

Show that perfect a perfect reflector is a conic section with Fermat's principle


1. The problem statement, all variables and given/known data
Show, using Fermat's principle, that perfect reflecting surfaces are conic sections.


2. Relevant equations
Equations for the ellipse, parabola and hyperbola


3. The attempt at a solution
Ok, the ellipse seems easy. All rays coming from one focus reflecting to the other focus travels an equal distance if the mirror is an ellipse, since that's the definition of the ellipse.
I'm having problems with the hyperbola. If I understand the question correctly, I'm supposed to show that the rays traveling from one focus to the other (virtual image) are equal in length, but they clearly arent.
Where is the error in my thinking?
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