
#1
Mar1909, 09:33 PM

P: 24

1. The problem statement, all variables and given/known data
Use the same device to separate singly charged CO_{2} having ^{12}C and ^{14}C. What are the radii of curvature? This is a follow up question based on a HW problem I answered last week. The original problem was this: A doubly charged helium atom is accelerated by a voltage 2700V. What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340T field? 2. Relevant equations r = mv/qB 3. The attempt at a solution I solved the original problem by saying q = 2e for the doubly charged He On accelerating through V volts 1/2mv^2 = qV = (2e)V Where v = velocity acquired v = squrt(4eV/m) = 2*squrt(eV/m) I figured out the mass to be m = 7.26 x 10^26kg And then plugging into the formula. Now this new follow up question is throwing me off a little bit. Based on the question asked and info given how would you seperate the CO_{2}? And what would be the charge q of the CO_{2}? Im thinking it would be the 6e from C + 8e(2) of O2 = 22e. Is this correct? Thanks! 



#2
Mar1909, 09:37 PM

Sci Advisor
HW Helper
P: 8,961

No it's only the extra charge you put on to isonise it  generally just one e




#3
Mar1909, 09:52 PM

P: 24




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