|Mar19-09, 09:33 PM||#1|
1. The problem statement, all variables and given/known data
Use the same device to separate singly charged CO2 having 12C and 14C. What are the radii of curvature?
This is a follow up question based on a HW problem I answered last week. The original problem was this:
A doubly charged helium atom is accelerated by a voltage 2700V. What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340-T field?
2. Relevant equations
r = mv/qB
3. The attempt at a solution
I solved the original problem by saying
q = 2e for the doubly charged He
On accelerating through V volts
1/2mv^2 = qV = (2e)V
Where v = velocity acquired
v = squrt(4eV/m) = 2*squrt(eV/m)
I figured out the mass to be m = 7.26 x 10^-26kg
And then plugging into the formula.
Now this new follow up question is throwing me off a little bit. Based on the question asked and info given how would you seperate the CO2? And what would be the charge q of the CO2? Im thinking it would be the 6e from C + 8e(2) of O2 = 22e. Is this correct? Thanks!
|Mar19-09, 09:37 PM||#2|
No it's only the extra charge you put on to isonise it - generally just one e-
|Mar19-09, 09:52 PM||#3|
|Similar Threads for: Seperate CO2|
|can i seperate co2||Biology, Chemistry & Other Homework||1|
|Spring Constant and Work (2 seperate problems)||Introductory Physics Homework||6|
|2 seperate sounds||Classical Physics||3|
|[SOLVED] Should Europe Be Considered A Seperate Continent?||Earth||52|
|Should Politics and World Affairs be a seperate forum?||Forum Feedback & Announcements||9|