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Number sequences hard 
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#1
Mar2109, 06:29 AM

P: 3

Hello All,
Well to make the Story short, I made a little bet in school that I could solve all the number sequences on a site, but now's the joke. I cant Ye ye , stop laughing But really I can handle myself at numbers normally pretty well, but this seems out of my league Can anyone solve this ? 2 3 27 69 129 … For those interested, this is the site, and was making the hard test ofc. http://www.fibonicci.com/en/numbersequences 3. The attempt at a solution It seems to be something like (x^n)y help :) 


#2
Mar2109, 06:48 AM

P: 655

You sure it doesnt start with 5?



#3
Mar2109, 06:53 AM

P: 3

yes i am sure it doesnt start with 5 :)
And I already mailed the website, but havent gotten any reply Have been cracking my brain on it for hours, it isn't funny anymore :( This is def. one of, if not the hardest test i made on the web lol. pwned :)) 


#4
Mar2109, 10:08 AM

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P: 21,400

Number sequences hard
I went to the site you posted and saw this problem among the hard problems group. The potential answers given are 178, 207, 268, and 312.
I choose 207. Here's my reasoning: 2 = the starting number 3 = 2^{2} + (1) 27 = 5^{2} + 2 69 = 8^{2} + 5 129 = 11^{2} + 8 The pattern here seems to be that the number being squared increases by 3 each time, and the number added to the square also increases by 3 each time. The next number in the list should be 14^{2} + 11 = 196 + 11 = 207, which just happens to be one of the possible answers. 


#5
Mar2109, 02:30 PM

P: 3

You're Awesome!
But doesnt taht make the start nuymber 3 (1^2)4 ^^ 


#6
Mar2109, 06:39 PM

Mentor
P: 21,400

Well, there's that.
Anyway, 2 = 3 for very small values of 2. 


#7
Mar2209, 01:09 AM

P: 287

These problems are all sort of dumb.
For each sequence, there are infinitely many rule sets you can generate which will give you any answer you can possibly concoct. With no restrictions on the rules, the game is an exercise in futility. 


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