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electric field across a parallel plate capacitor |
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| Mar22-09, 12:31 PM | #1 |
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electric field across a parallel plate capacitor
Hello,
If I had a potential source (V) , a resistor R, and a parallel plate capacitor, would the Electric field across the capacitor become E = (V - IR)/L L = distance between capacitor or would the electric field simply become E = V/L ?? thank you!! |
| Mar22-09, 01:47 PM | #2 |
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How is the circuit set up? Your E = (V - IR)/L would be correct for a purely series circuit. But the current would be zero (or quickly become zero as the capacitor charges) so your second formula is then correct.
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| Mar22-09, 01:47 PM | #3 |
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| Mar26-09, 11:15 PM | #4 |
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electric field across a parallel plate capacitor
Ah ic, oh okay I understand now.
so if in series, clearly initially it is E = (V-IR) /L but after the capcitor is fully charged then E = V/L however if in parallel from the start then E = V/L, always would this be correct? |
| Mar26-09, 11:33 PM | #5 |
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If the V, R and C are all in parallel then they all have the same potential V.
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