Composition of Linear Transformation and Matrix Multiplicationby jeff1evesque Tags: composition, linear, matrix, multiplication, transformation 

#1
Mar3009, 04:58 PM

P: 312

Theorem 2.15:
Let A be an m x n matrix with entries from F. Then the leftmultiplication transformation [tex]L_A: F^n > F^m[/tex]. Furthermore, if B is any other m x n matrix ( with entries from F ) and B and D are the standard ordered bases for [tex]F^n and F^m[/tex], respectively, then we have the following properties. (d.) If [tex]T: F^n > F^m[/tex] is linear, then there exists a unique m x n matrix C such that [tex]T = L_C[/tex]. In fact [tex]C = [T]_B ^D[/tex] proof: Let [tex] C = [T]_B ^D[/tex]. By Theorem 2.14, we have [tex][T(x)]_D = [T]_B ^D[x]_B[/tex] or T(x) = Cx = [tex]L_C(x)[/tex] for all x in [tex]F^n[/tex]. So T = [tex]L_C[/tex] In particular I dont understand how T(x) = Cx Thanks, JL 



#2
Mar3009, 05:26 PM

P: 876

You previously defined C to be the matrix of T with respect to the bases B and D. By theorem 2.14, you have the equivalence to [itex][T]_B ^D[x]_B[/itex], the next line is just replacing symbols with their equivalent matrix/vector forms.




#3
Mar3109, 08:13 AM

P: 312

thanks.



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