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Transverse wave equation period

 
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Apr10-09, 03:30 AM   #1
 

Transverse wave equation period


A transverse wave on a rope is given by [tex]y(x, t)=
(0.750\; {\rm cm})\, \cos ( \, \pi [(0.400\;{\rm cm}^{ - 1})x+(250\; {\rm s}^{ - 1})t])[/tex]


Find the period.

This should be simple, but I keep getting the wrong answer in Mastering Physics. I can't find any explanation in my book, and it's really irritating me.
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Apr10-09, 06:37 AM   #2
 
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Rewrite the equation in a standard form.
y(x,t) = Acos[2*pi(x/lambda + t/T)]
Compare this with the given equation and find the period.
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