# Three blocks and two pulleys

by Squeezebox
Tags: blocks, pulleys
 P: 58 1. The problem statement, all variables and given/known data The coefficient of kinetic friction between the two blocks is 0.30. The surface of the table and pulleys are frictionless. m1=2 kg m2=3 kg m3=10 kg 2. Relevant equations $$\Sigma$$F=ma T2-m3g=m3a T1-T2=m2a friction-T1=m1a 3. The attempt at a solution T2=m3g+m3a T1=friction-m1a friction-m1a-m3g-m3a=m2a (friction-m3g)/(m1+m2+m3)=a a=-6.15m/s2 The answer in my book say it is -5.7m/s2, though. Attached Thumbnails
P: 69
 Quote by Squeezebox 1. The problem statement, all variables and given/known data The coefficient of kinetic friction between the two blocks is 0.30. The surface of the table and pulleys are frictionless. m1=2 kg m2=3 kg m3=10 kg The answer in my book say it is -5.7m/s2, though.
T2=m3g-m3a
T1=m1a+m1
T2=T1+m1gμ+m2a
a=(m3g-m1gμ-m1gμ)/(m1+m2+m3)=5.7552

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