## Center Gravity and Moment of Inertia

1. The problem statement, all variables and given/known data
Four objects are held in position at the corners of a rectangle by light rods as shown in the figure below. The mass values are given below.
M1 (kg) M2 (kg) M3 (kg) M4 (kg)
3.50 1.50 3.90 1.70

(a) Find the moment of inertia of the system about the x axis.

(b) Find the moment of inertia of the system about the y axis.

(c) Find the moment of inertia of the system about an axis through O and perpendicular to the page.

2. Relevant equations

Center of Gravity: sumM1*X1+M1*X2.../M1+M2...

3. The attempt at a solution

I found the center of gravity for the x axis to be .037736...how do I find the moment of inertia with that information?

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 Recognitions: Homework Help You need to find the x and y CoM. Knowing that then the moment I about the CoM is Σmr2. The axes are simpler in that for I_x = Σm_i*y_i2 I_y = Σm_i*x_i2
 Oh, I reversed the two and that's why I got it wrong. Thanks. What would I use for part c?

Recognitions:
Homework Help

## Center Gravity and Moment of Inertia

 Quote by ymehuuh Oh, I reversed the two and that's why I got it wrong. Thanks. What would I use for part c?
What are the distances to each corner from O to each mass?

I_o = Σmr2

It's made a little easier by Pythagoras, so be sure and thank him.

 Quote by lowlypion what are the distances to each corner from o to each mass? I_o = Σmr2 it's made a little easier by pythagoras, so be sure and thank him.
perfect! Thanks!!