How to Compute the Derivative of a Complex Modulus Function

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Discussion Overview

The discussion revolves around calculating the derivative of a complex modulus function, specifically the function f(t) = |u(t) + i·v(t)|. Participants explore different methods for deriving this expression, focusing on the application of calculus principles such as the chain rule and implicit differentiation.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents the function f(t) = |u(t) + i·v(t)| and requests assistance in expressing its derivative in terms of u, u', v, and v'.
  • Another participant suggests using the chain rule and implicit differentiation, proposing to let a = u(t) + iv(t) and expressing the derivative as df/dt = (df/da)(da/dt).
  • A third participant reiterates the original function and proposes that |u(t) + i·v(t)| = u^2(t) + v^2(t), leading to the derivative f'(t) = 2(uu' + vv'), although they later acknowledge a mistake regarding the square root.
  • A different participant challenges the previous claims, stating that f = √(a^2) is incorrect and that df/da does not exist, suggesting instead to apply the definition of modulus directly to compute the derivative.

Areas of Agreement / Disagreement

Participants express differing views on the correct approach to calculating the derivative, with no consensus reached on the validity of the methods proposed. Some methods are challenged, indicating a lack of agreement on the best approach.

Contextual Notes

There are unresolved issues regarding the application of the chain rule and the definition of the modulus function, as well as potential misunderstandings about the existence of certain derivatives.

sigmund
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I have to calculate the derivative of this function:

[tex]f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert[/tex]

The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?
 
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Okay, this is a combination of the chain rule and implicit differentiation.

The first thing to do is let [tex]a=u(t)+iv(t)[/tex]

Now let [tex]f(x)=\sqrt{a^2}[/tex] and the derivative becomes

[tex]\frac{df}{dt}=\frac{df}{da}\frac{da}{dt}[/tex]

You should be able to proceed from there. If not, yell out.
 
sigmund said:
I have to calculate the derivative of this function:

[tex]f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert[/tex]

The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?


But [tex]\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert = u^2(t) + v^2(t)[/tex]

So, [tex]f'(t) = 2(uu' +vv')[/tex]


EDIT : forgot SQRT, but Hurkyl got it !
 
That won't work at all. In particular, [itex]f = \sqrt{a^2}[/itex] is incorrect and [itex]df/da[/itex] does not exist.


The most straightforward way to compute this derivative is to simply write out the function f. You recall that [itex]|x + iy| = \sqrt{x^2 + y^2}[/itex], right? Apply the definition of modulus, and you should get something you could do back in calc I.
 

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