| Thread Closed |
Need lots of help! :D |
Share Thread | Thread Tools |
| Jun1-09, 05:25 PM | #1 |
|
|
Need lots of help! :D
1. The problem statement, all variables and given/known data
A new rectangle with the word “STROM” is to be constructed inside the mat of an outside rectangle. The width of the mat surrounding the rectangular “STROM” logo will be the same. The area of the boundary around the word “STROM” will be the same as the logo itself. Determine the uniform width of the boundary. 2. Relevant equations i made a picture of it including the measurements from the sheet: ![]() 3. The attempt at a solution 294.5 inches x 72 inches = 21204 inches i really dont know what to do, please show me step-by-step directions on how to solve this so I can understand and learn from it. Thanks!!!!:) |
| Jun1-09, 06:43 PM | #2 |
|
|
You'll learn even better when you show us the step by step solution! You've done the first step correctly. The units are "square inches". Now there's more information you were given. Can you find any other areas? What else has an area in this problem?
|
| Jun1-09, 06:50 PM | #3 |
|
|
how am i to find the uniform width of the boundary?? |
| Jun1-09, 06:52 PM | #4 |
|
|
Need lots of help! :D |
| Jun1-09, 06:54 PM | #5 |
|
|
well there weren't any measurements given to the logo, so how would i go about finding its area? as far as i know, the measurements from the mat rectangle have to do with something with its area, right? i cant seem to figure it out though. =\
|
| Jun1-09, 07:22 PM | #6 |
|
|
Can that help tell you the area of the logo itself? You've already obtained the total area. |
| Jun1-09, 07:29 PM | #7 |
|
|
i still don't get it. :( i only got the total area which is 21204 inches. so you're saying its the same? so the logo's area is 21204 inches as well?
ah damn i suck at this...lol. |
| Jun1-09, 07:42 PM | #8 |
|
|
The total area is 21204. That area is a logo, and also a fixed width boundary.The logo is the same area as the boundary, and together they equal 21204. Whats the area of the logo? What's the area of the boundary? Cheers -- sylas |
| Jun1-09, 08:26 PM | #9 |
|
|
10602? i divided the total area by 2.
|
| Jun1-09, 08:34 PM | #10 |
|
|
Now the next bit is going to take a bit of algebra. There are several ways of doing it but they all get the same answer. Use a variable "w" to represent the width of the boundary. The logo is a smaller rectangle inside the big one. What is its length and width? You won't be able to give them as numbers just yet, but you can get an expressing using "w". |
| Jun1-09, 08:42 PM | #11 |
|
|
huh? I don't get it. :( so I have 10602 as the area, and now I need the legnth and width of it.
10602 = L x W how do I get the length & width when i have the areA? |
| Jun1-09, 09:06 PM | #12 |
|
|
For example. You have used L and W for the length and width of the logo. Now also use B for the width of the boundary. Can you write expression using L, W and B for the length and width of the whole mat? Length: 294.5 = ???[L,W,B] Width: 72 = ???[L,W,B] I'm also a big fan of drawing pictures. You can label your diagram with L, W and B, to show what lengths and widths they refer to in the problem. |
| Jun1-09, 09:11 PM | #13 |
|
|
can you just give me the answer? i know thats probably the right way to learn in ur opinion, but hear me out. if you give me the answer then i can see how you got there by going backwards. i think that'd be better because i really can't figure this out and I'm not really understanding you :(
|
| Jun1-09, 09:35 PM | #14 |
|
|
Here's the diagram I suggested for you, labeled with L, W and B. ![]() Can you give n expression in terms of the variables for the total length? 294.5 = ??? |
| Jun1-09, 09:43 PM | #15 |
|
|
294.5 = n
??? |
| Jun1-09, 09:48 PM | #16 |
|
|
But what I am asking now is for a new expression, which captures something you know about the problem. Specifically, the total length "n" can be given in terms of your other variables L, W and B in the diagram. n = ??? Replace the ??? with an expression involving the other variables. |
| Jun1-09, 10:20 PM | #17 |
|
|
is it...
294.5 = l + 2b 72 = w + 2b |
| Thread Closed |
| Thread Tools | |
Similar Threads for: Need lots of help! :D
|
||||
| Thread | Forum | Replies | ||
| T_T lots of questions | Introductory Physics Homework | 3 | ||
| lots more questions | Precalculus Mathematics Homework | 2 | ||
| lots of adding | Linear & Abstract Algebra | 8 | ||
| wow, lots of threads in GD | General Discussion | 6 | ||
| i need lots of help | Introductory Physics Homework | 2 | ||