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Finding the rate equation and rate constant |
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| Jun5-09, 01:18 PM | #1 |
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Finding the rate equation and rate constant
1. The problem statement, all variables and given/known data
The dissociation of a compound was studied by performing measurements of a quantity X that is proportional to the concentration of the compound. The values of X measured at various times are as follows: X--->1.82, 2.01, 2.31, 2.67, 3.80, 5.25 t/sec----> 521, 617, 749, 873, 1185, 1449 Use this information to form a rate equation and rate constant. 2. Relevant equations k= (ln {A(t)/A(0)})/t 3. The attempt at a solution Im having a bunch of problems with this question and need a bit of a jump start. 1) the value of X: I am not given units or anything. It could basically be anything right? 2) the question states that X is proportional to the concentration of the compound. It also implies that the compound is dissociating. If you noticed, as time goes on, X is increasing. If they are proportional to each other how can the compound dissociate when X is increasing. My only thought is that they are "inversely" proportional and the question just says proportional. 3) Assuming that X has units of concentration, I went ahead and calculated the rate constant and got virtually all the same values (implying first order reaction) but the values were all negative. This is because X is increasing. Can I safely assume that these values of X are to do with concentration and assume that they are products and therefore use numbers that decrease proportionally to the given values and come up with a positive rate equation? Thankyou for your time 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
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