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Approximation for Newton-Raphson Inverse Algorithm

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Jun19-09, 05:05 PM
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I am attempting to make an initial approximation for the inverse algorithm (1/x)


a = a*(2-(n*a))
'a' gets closer to the actual result each time the algorithm is preformed

The problem is finding the initial approximation. An exponential equation seems to fit the best

a = .5^n
The equation gets more accurate as n increases^x%29

I chose .5, because in binary, dividing by two is as simple as shifting to the right.

Is there any other way to make a close approximation that is better than .5^n?
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